Bouquetin défricheur
Créature : chèvre
À chaque fois que le Bouquetin défricheur attaque, les créatures que vous contrôlez acquièrent le piétinement et gagnent +X/+X jusqu'à la fin du tour, X étant la force la plus élevée parmi les créatures que vous contrôlez.
3/3
standard
future
historic
gladiator
pioneer
modern
legacy
pauper
vintage
penny
commander
brawl
alchemy
paupercommander
duel
oldschool
premodern
Rulings
The value of X is calculated as Pathbreaker Ibex’s ability resolves. Notably, if you attack with two Pathbreaker Ibex (and control no other creatures), the first ability to resolve will give those Ibex +3/+3. The second ability will then give them +6/+6.
If this creature’s power is negative as its ability resolves, X is considered to be 0. (This is a change from previous rulings.)
If the greatest power among creatures you control is negative as this creature’s ability resolves, X is considered to be 0.
If this creature’s power is negative as its ability resolves, X is considered to be 0. (This is a change from previous rulings.)
If the greatest power among creatures you control is negative as this creature’s ability resolves, X is considered to be 0.
Rulings
The value of X is calculated as Pathbreaker Ibex’s ability resolves. Notably, if you attack with two Pathbreaker Ibex (and control no other creatures), the first ability to resolve will give those Ibex +3/+3. The second ability will then give them +6/+6.
If this creature’s power is negative as its ability resolves, X is considered to be 0. (This is a change from previous rulings.)
If the greatest power among creatures you control is negative as this creature’s ability resolves, X is considered to be 0.
If this creature’s power is negative as its ability resolves, X is considered to be 0. (This is a change from previous rulings.)
If the greatest power among creatures you control is negative as this creature’s ability resolves, X is considered to be 0.
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